python 正则表达式 split 函数在 golang 中等效

import re
digits_re = re.compile("([0-9ee.+]*)")

p = digits_re.split("hello, where are you 1.1?")

print(p)

package main

import (
    "bytes"
    "fmt"
    "log"
    "os/exec"
    "regexp"
    "strconv"
)

func main() {
    // execute the command and get the output
    cmd := exec.command("echo", "hello, where are you 1.1?")
    var out bytes.buffer
    cmd.stdout = &out
    err := cmd.run()
    if err != nil {
        log.fatal(err)
    }

    // extract the numerical values from the output using a regular expression
    re := regexp.mustcompile(`([0-9ee.+]*)`)
    //matches := re.findallstring(out.string(), -1)
    splits := re.split(out.string(), -1)
    fmt.println(splits)

}

[H l l o ,   w h r   a r   y o u   ? 
]

// unfortunately go regex split doesn't work like python
    // so we construct the entire array with matched string (numericals)
    // and the split strings to combine the output
    splits := digitsre.split(string(out), -1)
    matches := digitsre.findallstring(string(out), -1)

    p := []string{}
    for i := 0; i < len(splits); i++ {
        p = append(p, matches[i])
        p = append(p, splits[i])
    }

[H e l l o ,   w h e r e   a r e   y o u  1.1 ?]