MYSQL中利用select查询某字段中包含以逗号分隔的字符串的记录方_MySQL

首先我们建立一张带有逗号分隔的字符串。CREATE TABLE test(id int(6) NOT NULL AUTO_INCREMENT,PRIMARY KEY (id),pname VARCHAR(20) NOT NULL,pnum VARCHAR(50) NOT NULL);然后插入带有逗号分隔的测试数据INSERT INTO test(pname,pnum) VALUES('产品1','1,2,4');INSERT INTO test(pname,pnum) VALUES('产品2','2,4,7');INSERT INTO test(pname,pnum) VALUES('产品3','3,4');INSERT INTO test(pname,pnum) VALUES('产品4','1,7,8,9');INSERT INTO test(pname,pnum) VALUES('产品5','33,4');查找pnum字段中包含3或者9的记录mysql> SELECT * FROM test WHERE find_in_set('3',pnum) OR find_in_set('9',pnum);+----+-------+---------+| id | pname | pnum    |+----+-------+---------+|  3 | 产品3 | 3,4     ||  4 | 产品4 | 1,7,8,9 |+----+-------+---------+2 rows in set (0.03 sec)使用正则mysql> SELECT * FROM test WHERE pnum REGEXP '(3|9)';+----+-------+---------+| id | pname | pnum    |+----+-------+---------+|  3 | 产品3 | 3,4     ||  4 | 产品4 | 1,7,8,9 ||  5 | 产品5 | 33,4    |+----+-------+---------+3 rows in set (0.02 sec)这样会产生多条记录，比如33也被查找出来了，不过MYSQL还可以使用正则，挺有意思的find_in_set()函数返回的所在的位置，如果不存在就返回0mysql> SELECT find_in_set('e','h,e,l,l,o');+------------------------------+| find_in_set('e','h,e,l,l,o') |+------------------------------+|                            2 |+------------------------------+1 row in set (0.00 sec)还可以用来排序，如下;mysql> SELECT * FROM TEST WHERE id in(4,2,3);+----+-------+---------+| id | pname | pnum    |+----+-------+---------+|  2 | 产品2 | 2,4,7   ||  3 | 产品3 | 3,4     ||  4 | 产品4 | 1,7,8,9 |+----+-------+---------+3 rows in set (0.03 sec)如果想要按照ID为4，2，3这样排序呢？mysql> SELECT * FROM TEST WHERE id in(4,2,3) ORDER BY find_in_set(id,'4,2,3');+----+-------+---------+| id | pname | pnum    |+----+-------+---------+|  4 | 产品4 | 1,7,8,9 ||  2 | 产品2 | 2,4,7   ||  3 | 产品3 | 3,4     |+----+-------+---------+3 rows in set (0.03 sec)