preg_replace按顺序替换相同的内容怎么实现？

<code><?php
$string = 'The quick brown fox jumped over the lazy dog.';
$patterns = array();
$patterns[0] = '/quick/';
$patterns[1] = '/brown/';
$patterns[2] = '/fox/';
$replacements = array();
$replacements[2] = 'slow';
$replacements[1] = 'black';
$replacements[0] = 'bear';
echo preg_replace($patterns, $replacements, $string);
?>
</code>

<code>The slow black bear jumped over the lazy dog.</code>

<code>$string = "your text";
$array = $your_row;
$count = 1;
function your_call_back($matches){
    global $count;
    $count = intval($count++);
    // 此处$count的值是你调用次数的值，如果需要考虑是否会数组越界的话，可以
    // isset$array[$count] 获取数组是否越界
    return "替换后的内容".$array[$count]."_".$count;
}
echo preg_replace_callback('/alt=""/',"your_call_back",$string);
</code>

<code><?php
$i = 0;
function cb($m) {
    $replace_arr = ['111', '222', '333'];
    global $i;
    $replace_str = $replace_arr[$i++] ? : $replace_arr[$i=0];
    return '替换后的内容'.$replace_str;
}
echo preg_replace_callback('/alt=""/', 'cb', $str);
</code>