数据如下
id domain port email type name value ttl route def remark
2390 test.cn 80 123@qq.com 1 www 123.123.123.123 0 0 0
2523 test.cn 80 123@qq.com 1 www 123.123.123.123 1800 0 0
一个表中有 2 条相同的数据,(除了 ttl 和 id 不一样外),现在要保留最新的一条记录(如 2523 ),请教如何操作
下面是需要用到的测试语句; 数据库是 mysql 5.7
use test;
CREATE TABLE test (
`id` int(11) NOT NULL AUTO_INCREMENT,
`domain` varchar(100) COLLATE utf8_unicode_ci NOT NULL,
`port` varchar(6) COLLATE utf8_unicode_ci DEFAULT '80',
`email` varchar(45) COLLATE utf8_unicode_ci NOT NULL,
`type` tinyint(4) DEFAULT NULL,
`name` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL,
`value` varchar(100) COLLATE utf8_unicode_ci DEFAULT NULL,
`ttl` int(11) DEFAULT '0',
`route` tinyint(4) DEFAULT '0',
`def` tinyint(1) DEFAULT '0',
`remark` varchar(100) COLLATE utf8_unicode_ci DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=2721 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci
INSERT INTO test.test (`id`, `domain`, `port`, `email`, `type`, `name`, `value`, `ttl`, `route`, `def`, `remark`) VALUES ('2390', 'www.test.cn', '80', '123@qq.com', '1', 'www', '123.123.123.123', '0', '0', '0', NULL);
INSERT INTO test.test (`id`, `domain`, `port`, `email`, `type`, `name`, `value`, `ttl`, `route`, `def`, `remark`) VALUES ('2523', 'www.test.cn', '80', '123@qq.com', '1', 'www', '123.123.123.123', '1800', '0', '0', NULL);
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踩我的出来指出错误呀,让我学习学习哪里有问题。
delete from test
where (id,
domain
,port
,email
,type
,name
,value
,route
,def
,remark
) not in (select * from (
select max(id) id,
domain
,port
,email
,type
,name
,value
,route
,def
,remark
from test group by
domain
,port
,email
,type
,name
,value
,route
,def
,remark
) tmp)select max(id),domain, port, email, type, name, value,route, def, remark from test GROUP BY domain, port, email, type, name, value,route, def, remark;
给你个生成删除脚本的sql