简陋版~, 对于ip的合法性没有做匹配, 仅仅匹配符合x.x.x.1

import re
ip_list = [
    '1.2.2.1',
    '1.2.3.3',
    '16.25.22.1',
    '112.23.22.1',
    '11.2.2.1',
    '1.2.32.11',
]
ip_regx = re.compile(r'(?:[\d]+\.)+1$')
for _ in ip_list:
    if re.search(ip_regx, _):
        print _