select pid,count(*) from table1 group by pid;
查出每个 pid 出现的总次数，
问题出来了，
另一个表里放了pid对应的name，
现在需要通过联合查询，直接显示出 ，
每个name出现的总次数
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SELECT a.pid as pid , a.name as name, COUNT(b.pid ) as num FROM `table1` as a, `table2` as b WHERE a.pid = b.pid;