Symfony实体参数转换器无法正确获取路由项
P粉885562567
2023-08-28 22:55:25
[PHP讨论组]
<p>我有一个需要获取类别和子类别的路由，路由的形式如下：</p>
<pre class="brush:php;toolbar:false;">#[Route('/{slug}/{subSlug}', name: 'subcategory')]
#[Entity('category', expr: 'repository.findOneBySlug(slug)')]
#[Entity('subcategory', expr: 'repository.findOneBySlug(subSlug)')]
public function subcat(Category $cat, Subcategory $sub): Response</pre>
<p>我尝试访问 <code>/mtg/dmr</code>，但是我得到了一个404的对象未找到错误，由@ParamConverter引起。
当我在Doctrine日志中查看时，系统在正确的表中查找，但是对于两个都在寻找<code>mtg</code>而不是先找<code>mtg</code>然后找<code>dmr</code>。有什么想法是怎么回事吗？</p>
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DOC示例：
#[Route('/blog/{date}/{slug}/comments/{comment_slug}')] #[ParamConverter('post', options: ['mapping' => ['date' => 'date', 'slug' => 'slug']])] #[ParamConverter('comment', options: ['mapping' => ['comment_slug' => 'slug']])] public function showComment(Post $post, Comment $comment) { }所以，在您的情况下，您必须有：
#[Route('/{slug}/{subSlug}', name: 'subcategory')] #[ParamConverter('cat', options: ['mapping' => ['slug' => 'slug']])] #[ParamConverter('sub', options: ['mapping' => ['subSlug' => 'slug']])] public function (Category $cat, Subcategory $sub): Response { }