遇到问题的表单验证，请指出问题所在（PHP验证）-PHP中文网问答

我想知道在我的代码中表单出了什么问题。

<?php

if(isset($_POST['submit'])) {
  $arrayName = array("TeacherA", "TeacherB", "TeacherC" , "TeacherD", "TeacherE");

  $minimum = 5;
  $maximum = 10;

  $name = $_POST['yourName'];
  $email = $_POST['yourEmail'];

  if(strlen($name) < $minimum) {
    echo "Your name should be longer than 5 characters";
  } 
  
  if(strlen($name) > $maximum) {
    echo "Your name should not be longer than 10 characters";
  } 
  
  if(!in_array($name,$arrayName)){
    echo "Please do register with us before you can login";
  } else {
    echo "Welcome!";
  }
}
?>

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>Blank</title>
</head>
<body>
  <form action="form.php" method="post">
    <label>Your Name:    </label>
    <input type="text" name="yourName"> <br>

    <label for="">Your E mail:</label>
    <input type="email" name="yourEmail" id=""><br>
    
    <!-- <textarea name="yourMessage" id="" cols="30" rows="10"></textarea><br> -->
    <input type="submit" name="submit" value="submit">
  </form>
</body>
</html>

我在本地运行了代码，但是无法得到我想要的结果。

我想要的结果是，如果我没有在“Your Name”字段中输入姓名，那么应该显示结果：

请在登录前先注册

<?php if (isset($_POST['submit'])) { $arrayName = array("TeacherA", "TeacherB", "TeacherC", "TeacherD", "TeacherE"); $minimum = 5; $maximum = 10; $name = $_POST['yourName']; $email = $_POST['yourEmail']; if (empty($name)) { echo "Please do register with us before you can login"; } else { if (strlen($name) < $minimum) { echo "Your name should be longer than 5 characters"; } else { if (strlen($name) > $maximum) { echo "Your name should be less than 10 characters"; } else { if (in_array($name, $arrayName)) { echo "Welcome!"; } else { echo "Your login is not correct"; } } } } } ?>

全部回复(1)

P粉2327937652023-09-10 13:59:13 1楼

如果“Your Name”字段为空，则其strlen($name)应为0，第一个if语句为真，并显示Your name should be longer than 5 characters 你可以尝试这个：

i used empty() to test if the field empty and i used if-else statements because i want the script to stop if it founds a 'true' condition in your script you can use return; but that will exit the rest of your script

have a nice code :)

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