我最近开始使用 MySQL 5.7.10,我非常喜欢原生 JSON 数据类型。
但是在更新 JSON 类型值时我遇到了问题。
问题:
下面是表格格式,这里我想在 data 列中为 t1 表添加 1 个键。现在我必须获取值修改它并更新表。所以就涉及到一个额外的SELECT语句。
我可以这样插入
INSERT INTO t1 values ('{"key2":"value2"}', 1);
mysql> select * from t1;
+--------------------+------+
| data | id |
+--------------------+------+
| {"key1": "value1"} | 1 |
| {"key2": "value2"} | 2 |
| {"key2": "value2"} | 1 |
+--------------------+------+
3 rows in set (0.00 sec)
mysql>Show create table t1;
+-------+-------------------------------------------------------------
-------------------------------------------------------+
| Table | Create Table |
+-------+--------------------------------------------------------------------------------------------------------------------+
| t1 | CREATE TABLE `t1` (
`data` json DEFAULT NULL,
`id` int(11) DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1 |
+-------+--------------------------------------------------------------------------------------------------------------------+
1 row in set (0.00 sec)
有解决办法吗?
Copyright 2014-2025 https://www.php.cn/ All Rights Reserved | php.cn | 湘ICP备2023035733号
感谢@wchiquito 为我指明了正确的方向。我解决了这个问题。这是我的做法。
mysql> select * from t1; +----------------------------------------+------+ | data | id | +----------------------------------------+------+ | {"key1": "value1", "key2": "VALUE2"} | 1 | | {"key2": "VALUE2"} | 2 | | {"key2": "VALUE2"} | 1 | | {"a": "x", "b": "y", "key2": "VALUE2"} | 1 | +----------------------------------------+------+ 4 rows in set (0.00 sec) mysql> update t1 set data = JSON_SET(data, "$.key2", "I am ID2") where id = 2; Query OK, 1 row affected (0.04 sec) Rows matched: 1 Changed: 1 Warnings: 0 mysql> select * from t1; +----------------------------------------+------+ | data | id | +----------------------------------------+------+ | {"key1": "value1", "key2": "VALUE2"} | 1 | | {"key2": "I am ID2"} | 2 | | {"key2": "VALUE2"} | 1 | | {"a": "x", "b": "y", "key2": "VALUE2"} | 1 | +----------------------------------------+------+ 4 rows in set (0.00 sec) mysql> update t1 set data = JSON_SET(data, "$.key3", "I am ID3") where id = 2; Query OK, 1 row affected (0.07 sec) Rows matched: 1 Changed: 1 Warnings: 0 mysql> select * from t1; +------------------------------------------+------+ | data | id | +------------------------------------------+------+ | {"key1": "value1", "key2": "VALUE2"} | 1 | | {"key2": "I am ID2", "key3": "I am ID3"} | 2 | | {"key2": "VALUE2"} | 1 | | {"a": "x", "b": "y", "key2": "VALUE2"} | 1 | +------------------------------------------+------+ 4 rows in set (0.00 sec)编辑: 如果要添加数组,请使用
JSON_ARRAY就像update t1 set data = JSON_SET(data, "$.key4", JSON_ARRAY('Hello','World!')) where id = 2;