获取数组对象中特定键值对的方法-PHP中文网问答

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获取数组对象中特定键值对的方法

P粉604669414 2024-01-16 11:23:03

[Vue.js讨论组]

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records = [{id: 231, first_name: "Jack", last_name: "Aston", email: "jack55@xyz.com"}, {id: 232, first_name: "Roy", last_name: "Dillon", email: "roy@xy.com"}, {id: 233, first_name: "Jacy", last_name: "Wilson", email: "jacy@x.com"}]

fields = ['id', 'email', 'last_name']

如何从记录中仅获取“id”、“email”和“last_name”，以便数据在 JavaScript 中如下所示？

new_records = [{id: 231, email: "jack55@xyz.com", last_name: "Aston"}, {id: 232, email: "roy@xy.com", last_name: "Dillon"}, {id: 233, email: "jacy@x.com", last_name: "Wilson"}]

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P粉8608979432024-01-17 09:07:28 2楼

const newRecords=records.map(item=>{return {id,email,last_name}})

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P粉0578693482024-01-17 00:07:18 1楼

const records = [{id: 231, first_name: "Jack", last_name: "Aston", email: "jack55@xyz.com"}, {id: 232, first_name: "Roy", last_name: "Dillon", email: "roy@xy.com"}, {id: 233, first_name: "Jacy", last_name: "Wilson", email: "jacy@x.com"}]

const fields = ['id', 'email', 'last_name']

console.log(records.map(i=>Object.fromEntries(fields.map(f=>[f, i[f]]))))

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