javascript - js数组中删除重复对象有什么快速的方法-PHP中文网问答

var term_gpa = [ { year: '2013-2014', term: '1' },
{ year: '2013-2014', term: '1' },
{ year: '2013-2014', term: '1' },
{ year: '2013-2014', term: '1' },
{ year: '2013-2014', term: '1' },
{ year: '2013-2014', term: '1' },
{ year: '2013-2014', term: '1' },
{ year: '2013-2014', term: '1' },
{ year: '2013-2014', term: '1' },
{ year: '2013-2014', term: '2' },
{ year: '2013-2014', term: '2' },
{ year: '2013-2014', term: '2' },
{ year: '2013-2014', term: '2' },
{ year: '2013-2014', term: '2' },
{ year: '2013-2014', term: '2' },
{ year: '2013-2014', term: '2' },
{ year: '2013-2014', term: '2' },
{ year: '2013-2014', term: '2' },
{ year: '2013-2014', term: '2' },
{ year: '2013-2014', term: '2' },
{ year: '2013-2014', term: '2' },
{ year: '2014-2015', term: '1' },
{ year: '2014-2015', term: '1' },
{ year: '2014-2015', term: '1' },
{ year: '2014-2015', term: '1' },
{ year: '2014-2015', term: '1' },
{ year: '2014-2015', term: '1' },
{ year: '2014-2015', term: '1' },
{ year: '2014-2015', term: '1' },
{ year: '2014-2015', term: '1' },
{ year: '2014-2015', term: '1' },
{ year: '2014-2015', term: '1' },
{ year: '2014-2015', term: '1' },
{ year: '2014-2015', term: '1' },
{ year: '2014-2015', term: '1' } ]

比如上面那个要变成
var term_gpa = [{ year: '2013-2014', term: '1' },
{ year: '2013-2014', term: '2' },
{ year: '2014-2015', term: '1' } ]

全部回复(4)

PHP中文网2017-04-10 15:12:05 4楼

var unique = {};
term_gpa.forEach(function(gpa){ unique[ JSON.stringify(gpa) ] = gpa });
term_gpa = Object.keys(unique).map(function(u){return JSON.parse(u) });

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黄舟2017-04-10 15:12:05 3楼

最快的方法是利用字典，遍历一次你的数组，将year和term设为数组的键：
var myArr = []; for(var item in term_gpa){ myArr[':'+item.year +':'+item.term] = item; };
OK, myArr就是你要的去重的数组了。