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用了preg_filter()函数,老提示Call to undefined function preg_filter() ,怎么回事啊?
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php//php 5.3- if (!function_exists('preg_filter')) { function preg_filter($pattern, $replace, $subject, $limit = -1 , &$count = null) { if(!is_array($subject)) { $noArray = 1 ; $subject = array($subject); } $preg = preg_replace($pattern, $replace, $subject, $limit, &$count); $diff = array_diff($preg, $subject); if($noArray == 1) $diff = implode($diff) ; return $diff ; } }
php
//php 5.3- if (!function_exists('preg_filter')) { function preg_filter($pattern, $replace, $subject, $limit = -1 , &$count = null) { if(!is_array($subject)) { $noArray = 1 ; $subject = array($subject); } $preg = preg_replace($pattern, $replace, $subject, $limit, &$count); $diff = array_diff($preg, $subject); if($noArray == 1) $diff = implode($diff) ; return $diff ; } }
看下是不是PHP版本问题,这个函数应该是 5.3+之后的
preg_filter (PHP 5 >= 5.3.0) preg_filter — Perform a regular expression search and replace
可以用了,但前提必须是php5.3或以上的,都怪自己在编辑器里面没配置好才会出现这个错误的,I'm sorry~
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看下是不是PHP版本问题,这个函数应该是 5.3+之后的
preg_filter
(PHP 5 >= 5.3.0)
preg_filter — Perform a regular expression search and replace
可以用了,但前提必须是php5.3或以上的,都怪自己在编辑器里面没配置好才会出现这个错误的,I'm sorry~