http - java服务器获取远端ip地址-PHP中文网问答

文章专题 AI工具学习下载问答源码最近更新

PHP

会员中心讲师中心微信公众号

http - java服务器获取远端ip地址

PHP中文网 2017-04-17 13:03:22

[Java讨论组]

598

public String getIpAddr(HttpServletRequest request) {  

    String ip = request.getHeader("x-forwarded-for");  
    if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
        ip = request.getHeader("Proxy-Client-IP");  
    }  
    if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
        ip = request.getHeader("WL-Proxy-Client-IP");  
    }  
    if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
        ip = request.getRemoteAddr();  
    }  
    System.out.println("本次登录的用户IP地址："+ ip);
    return ip;
}

这里面的参数request在play！里面怎么传进去，或者play！有它本身获得ip地址的api吗？

PHP中文网

认证0级讲师

全部回复(1)

大家讲道理2017-04-17 13:05:22 1楼

Play Framework 中没有 HttpServletRequest，也不需要

你的代码可以改成

public String getIpAddr() {  

    Request req = request();
    String ip = req.getHeader("x-forwarded-for");  
    if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
        ip = req.getHeader("proxy-client-ip");  
    }  
    if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
        ip = req.getHeader("wl-proxy-client-ip");  
    }  
    if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
        ip = req.remoteAddress();  
    }  
    System.out.println("本次登录的用户IP地址："+ ip);
    return ip;
}

赞 +0

添加回复

专题推荐

更多>

热门话题

热门教程

更多>