查 gift_id 为1004302的用户存list1 查 gift_id 为1004004的用户存list2 两个list取交集

select t.user_id, count(1) as c from table as t
where t.gift_id in(1004302, 1004004)
group by t.user_id
having count(1)>1

效率问题, 没数据, 也测试不了

如果, (user_id, gift_id) 是有可能重复的, 那在计算同时拥有之前还得将 (user_id, gift_id) 去重.

select t.user_id, count(1) as c from (
select user_id, gift_id from table group by user_id, gift_id
) as t
where t.gift_id in(1004302, 1004004)
group by t.user_id
having count(1)>1