试试这个？

public static void main(String[] args) {
    Document doc = null;//这里是你自己获取的Document对象

    Element share = doc.getElementById("bdshare");
    String data = share.getAttribute("data");

    Gson gson = new Gson();
    Data dd = gson.fromJson(data, Data.class);
    System.out.println(dd.getText());
}

class Data {
    private String comment;
    private String desc;
    private String text;
    private String title;
    private String url;
    private String pic;

    public String getComment() {
        return comment;
    }

    public void setComment(String comment) {
        this.comment = comment;
    }
    public String getDesc() {
        return desc;
    }

    public void setDesc(String desc) {
        this.desc = desc;
    }

    public String getText() {
        return text;
    }

    public void setText(String text) {
        this.text = text;
    }

    public String getTitle() {
        return title;
    }

    public void setTitle(String title) {
        this.title = title;
    }

    public String getUrl() {
        return url;
    }

    public void setUrl(String url) {
        this.url = url;
    }

    public String getPic() {
        return pic;
    }

    public void setPic(String pic) {
        this.pic = pic;
    }
}

eval("var a="+window.document.getElementById('bdshare').getAttribute('data'))
console.log(a.title)

var el = document.getElementById('bdshare')
var data = JSON.parse(el.getAttribute('data'))
//title
alert(data.title)
//text
alert(data.text)

比较同意用json parse的方法。

有三种方法来实现：
var data = window.document.getElementById('bdshare').getAttribute('data');

1. var json = JSON.parse(data);

2. eval('(' + data + ')');

3. var a = new Function("return " + data); a();

doucumentby 或者用jquery