java - retrofit2.0 post提交一直返回400,用httpurlconnection就可以-PHP中文网问答

1.用retrofit2.0 post提交 json
@POST("AppLoginIn")

Call<JsonObject> getLoginUser(@Body String parameterJson);

//待提交的json数据
private String toJsonUser() {

    JSONStringer jsonStringer = null;
    try {
        jsonStringer = new JSONStringer().object().key("LoginCode").value("SUPERMAN").key("Password")
                .value("111111").endObject();
    } catch (JSONException e) {
        e.printStackTrace();
    }
    Log.i("", "---json user:" + jsonStringer.toString());
    return jsonStringer.toString();
}
//retrofit 请求
 private void postYDL(String jsonString) {
    Retrofit retrofit = new Retrofit.Builder().baseUrl(url)
            .addConverterFactory(GsonConverterFactory.create())
            .build();
    IService iService = retrofit.create(IService.class);
    Call<JsonObject> call = iService.getLoginUser(jsonString);
    call.enqueue(new Callback<JsonObject>() {
        @Override
        public void onResponse(Call<JsonObject> call, Response<JsonObject> response) {
            String responseData = "---body:" + response.body()

"n---message:" + response.message()
"n---headers:" + response.headers()
"n---code:" + response.code()

"n---isSuccessful:" + response.isSuccessful();

           Log.i("", "---base action responseData:" + responseData);
           tv1.setText(responseData);
       }

       @Override

void onFailure(Call<JsonObject> call, Throwable t) {
```
           tv1.setText(t.getMessage());
       }
   });
```
}

换另一个请求地址结果: