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实现任意两个数的加减乘除

原创 2019-03-16 11:41:34 751
摘要:function computer($num1,$num2,$opt){switch($opt){case "+":$reslut = $num1+$num2;break;case "-":$reslut = $num1-$num2;break;case "*":$reslut = $num1*$num2;break;case "

function computer($num1,$num2,$opt){

switch($opt){

case "+":

$reslut = $num1+$num2;

break;

case "-":

$reslut = $num1-$num2;

break;

case "*":

$reslut = $num1*$num2;

break;

case "/":

$reslut =  $num2==0? '错误':$num1/$num2;

break;

default:

$reslut="错误";

}

return $reslut;

}


echo computer(10,5,*);

批改老师:天蓬老师批改时间:2019-03-16 13:07:18
老师总结:这个案例,你学到了什么呢? 不想谈谈吗?

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