Java 多线程同步之谜：如何避免共享变量 lt_num2 的竞争条件？

public class ThreadExample {

    // 使用 ReentrantLock 锁机制
    private static ReentrantLock lock = new ReentrantLock();

    public static void main(String[] args) {
        int lt_num2 = 1;

        // 创建一个线程池，线程数与您要处理的业务逻辑数量相同
        ExecutorService executorService = Executors.newFixedThreadPool(20);

        // 遍历需要处理的业务逻辑
        for (int i = 1; i <= 20; i++) {
            executorService.submit(() -> {
                lock.lock();
                try {
                    // 同步代码块
                    num(lt_num2);
                    lt_num2++;
                } finally {
                    lock.unlock();
                }
            });
        }

        executorService.shutdown();
        executorService.awaitTermination(1, TimeUnit.MINUTES);
    }

    private static void num(int num) {
        // 业务处理逻辑
        System.out.println("当前处理数字：" + num);
    }
}