
关于go读取xml中worksheet的问题
问题:如何正确提取go中xml数据中存储的excel worksheet结构?
答案:
可以使用标准库 encoding/xml 解析xml并提取worksheet数据。
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代码示例:
package main
import (
"encoding/xml"
"fmt"
)
// Workbook represents the XML structure of an Excel workbook.
type Workbook struct {
Worksheet Worksheet `xml:"Worksheet"`
}
// Worksheet represents the XML structure of a worksheet.
type Worksheet struct {
Table Table `xml:"Table"`
}
// Table represents the XML structure of a table within a worksheet.
type Table struct {
Rows []Row `xml:"Row"`
}
// Row represents the XML structure of a row within a table.
type Row struct {
Cells []Cell `xml:"Cell"`
}
// Cell represents the XML structure of a cell within a row.
type Cell struct {
Value string `xml:"Data"`
}
func main() {
var book Workbook
err := xml.Unmarshal([]byte(xmldata), &book)
if err != nil {
fmt.Println(err)
return
}
// Access the worksheet data
for _, row := range book.Worksheet.Table.Rows {
for _, cell := range row.Cells {
fmt.Println(cell.Value)
}
}
}
// Sample XML data representing an Excel worksheet
var xmldata = `
<?xml version="1.0"?>
<?mso-application progid="Excel.Sheet"?>
<Workbook
xmlns="urn:schemas-microsoft-com:office:spreadsheet"
xmlns:o="urn:schemas-microsoft-com:office:office"
xmlns:x="urn:schemas-microsoft-com:office:excel"
xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet">
<Worksheet ss:Name="Sheet">
<Table>
<Row>
<Cell><Data>Column 1</Data></Cell>
<Cell><Data>Column 2</Data></Cell>
<Cell><Data>Column 3</Data></Cell>
</Row>
<Row>
<Cell><Data>Row 2, Column 1</Data></Cell>
<Cell><Data>Row 2, Column 2</Data></Cell>
<Cell><Data>Row 2, Column 3</Data></Cell>
</Row>
</Table>
</Worksheet>
</Workbook>`要点:
请注意,提供的代码仅展示了基本的工作原理。实际实现可能需要针对具体用例进行调整和扩展。
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