用 Python 的 Turtle 模块绘制星号组成的正方形，应该怎么做？

import turtle
turtle.shape('classic')
turtle.speed(10)
turtle.setpos(0,0)

def make_star(pos, n):
    turtle.penup()
    turtle.setpos(pos)
    turtle.pendown()
    turtle.right(30)
    turtle.forward(n)
    turtle.back(n*0.5)
    turtle.right(120)
    turtle.forward(n*0.5)
    turtle.back(n)
    turtle.forward(n*0.5)
    turtle.right(120)
    turtle.forward(n*0.5)
    turtle.back(n)
    turtle.forward(n*0.5)
    turtle.right(90)

def make_square(left_bottom, right_top, size = 10):
    # left_top: 对角左下顶点坐标
    # right_bottom: 对角右上顶点坐标
    # size: *的大小
    x1, y1 = left_bottom
    x2, y2 = right_top

    if x1 > x2:
        raise Exception('left_bottom参数错误')
    if y1 > y2:
        raise Exception('right_top参数错误')
    if x2-x1 < size*3:
        raise Exception('size参数错误，size至多是边长的三分之一长度')
    if y2-y1 < size*3:
        raise Exception('size参数错误，size至多是边长的三分之一长度')

    # 第一条边 一
    for i in range(x1, x2, size):
        turtle.penup()
        turtle.setpos((x1 + i, y1))
        turtle.pendown()
        turtle.write('*', font=size)

    # 第二条边 一 |
    for i in range(y1, y2, size):
        turtle.penup()
        turtle.setpos((x2, y1 + i))
        turtle.pendown()
        turtle.write('*', font=size)

    # 第三条边 一 | 一
    for i in range(x1, x2, size):
        turtle.penup()
        turtle.setpos((x2 - i, y2))
        turtle.pendown()
        turtle.write('*', font=size)

    # 第四条边 一 | 一 |
    for i in range(y1, y2, size):
        turtle.penup()
        turtle.setpos((x1, y2 - i))
        turtle.pendown()
        turtle.write('*', font=size)
    
make_square((0,0), (100, 100), 10)
turtle.done()