<code class="lang-javascript"> var uinfo = {};
var uname = document.getElementById('uname');
var upwd = document.getElementById('upwd');
uinfo['uname'] = uname.value;
uinfo['upwd'] = upwd.value;
var usent = JSON.stringify(uinfo);
var xhr = null;
if(window.XMLHttpRequest){
xhr = new XMLHttpRequest();
}else{
xhr = ActiveXObject('Microsoft.XMLHttp');
}
xhr.open("POST", "/controler/login.php",true);
//etc
xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
xhr.send(usent);
</code>然后php端怎么接受js发送的数据呢?
$_POST['']
拿不到数据,这部分的格式具体是要指定呢,求大神指导下~~
多谢~!
<code class="lang-javascript"> var uinfo = {};
var uname = document.getElementById('uname');
var upwd = document.getElementById('upwd');
uinfo['uname'] = uname.value;
uinfo['upwd'] = upwd.value;
var usent = JSON.stringify(uinfo);
var xhr = null;
if(window.XMLHttpRequest){
xhr = new XMLHttpRequest();
}else{
xhr = ActiveXObject('Microsoft.XMLHttp');
}
xhr.open("POST", "/controler/login.php",true);
//etc
xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
xhr.send(usent);
</code>然后php端怎么接受js发送的数据呢?
$_POST['']
拿不到数据,这部分的格式具体是要指定呢,求大神指导下~~
多谢~!
答案太弱了...
Easily find JSON paths within JSON objects using our intuitive Json Path Finder
30
<code>xhr.send('json='+usent);
</code>
你可以用file_get_contents(‘php://input’);尝试打印看看是什么,可以去看看这一篇文章
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