Go语言中：如何将字符串数组中的十六进制数据转换为uint8数组？

func main() {
    // 直接使用十六进制字面量创建字节数组，再转换为字符串
    cardbill := []string{string([]byte{0x00, 0xb2, 0x01, 0x5c, 0x00}), string([]byte{0x00, 0xb2, 0x02, 0x5c, 0x00})}
    // 原始字节数组
    original := []byte{0x00, 0xb2, 0x01, 0x5c, 0x00}

    // 转换回字节数组
    converted, _ := hex.DecodeString(cardbill[0]) // 使用hex.DecodeString进行解码

    fmt.Println("Original:", original)
    fmt.Println("Converted:", converted)
}

import (
    "fmt"
    "strconv"
    "strings"
)

func main() {
    cardBill := []string{"0x00, 0xb2, 0x01, 0x5c, 0x00", "0x00, 0xb2, 0x02, 0x5c, 0x00"}
    original := []byte{0x00, 0xb2, 0x01, 0x5c, 0x00}

    var converted []byte
    for _, hexString := range strings.Split(cardBill[0], ",") {
        hexString = strings.TrimSpace(hexString)
        if len(hexString) > 2 && hexString[:2] == "0x" {
            hexString = hexString[2:] // Remove "0x" prefix if present
        }
        num, err := strconv.ParseUint(hexString, 16, 8)
        if err != nil {
            panic(err)
        }
        converted = append(converted, uint8(num))
    }

    fmt.Println("Original:", original)
    fmt.Println("Converted:", converted)
}