=背景介绍 -tableSales表 -第一次查询(2013销售员销售总额) select salesName, sum(extendedPrice) as sumprice13 from tableSales where salesTime between '2013-01-01' and '2013-12-31' group by salesName -第二次查询(2014销售员销售总额) select sale
=>背景介绍
->tableSales表
->第一次查询(2013销售员销售总额)
select salesName, sum(extendedPrice) as sumprice13 from tableSales where salesTime between '2013-01-01' and '2013-12-31' group by salesName
->第二次查询(2014销售员销售总额)
select salesName, sum(extendedPrice) as sumprice14 from tableSales where salesTime between '2014-01-01' and '2014-12-31' group by salesName
->如何获得销售员13、14年的销售总额?
A、首先,我想到的就是用union all,但不理想;
select salesName, sum(extendedPrice) as sumprice13, null as sumprice14 from tableSales where salesTime between '2013-01-01' and '2013-12-31' group by salesName
union all
select salesName, null as sumprice13, sum(extendedPrice) as sumprice14 from tableSales where salesTime between '2014-01-01' and '2014-12-31' group by salesName
B最后,通过fredrickhu版主大大的指点,修改如下:
SELECT
a.salesName, a.sumprice13, b.sumprice14
FROM
(SELECT
salesName, SUM(extendedPrice) AS sumprice13
FROM
tableSales
WHERE
salesTime BETWEEN '2013-01-01' AND '2013-12-31'
GROUP BY
salesName
) AS a
INNER JOIN
(SELECT
salesName, SUM(extendedPrice) AS sumprice14
FROM
tableSales
WHERE
salesTime BETWEEN '2014-01-01' AND '2014-12-31'
GROUP BY
salesName
) AS b
ON a.salesName=b.salesName
最后再次感谢fredrickhu大大!谢谢!..风雨兼程...
每个人都需要一台速度更快、更稳定的 PC。随着时间的推移,垃圾文件、旧注册表数据和不必要的后台进程会占用资源并降低性能。幸运的是,许多工具可以让 Windows 保持平稳运行。
Copyright 2014-2025 https://www.php.cn/ All Rights Reserved | php.cn | 湘ICP备2023035733号