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Python 统计列表中元素出现次数的完整指南

心靈之曲

发布： 2025-07-12 19:22:01

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python 统计列表中元素出现次数的完整指南

本文旨在介绍如何使用 Python 统计列表中每个元素出现的次数，并按照出现次数从多到少进行排序输出。我们将探讨使用 collections.Counter 类的简洁方法, 并提供代码示例和注意事项，帮助读者快速掌握这一实用技巧。

使用 collections.Counter 统计元素出现次数

Python 的 collections 模块提供了一个名为 Counter 的类，专门用于统计可哈希对象的出现次数。它是一个字典的子类，其中元素作为键，它们的计数作为值。

以下是如何使用 Counter 统计列表中元素出现次数的示例：

from collections import Counter

sample_list = ["a", "ab", "a", "abc", "ab", "ab"]
element_counts = Counter(sample_list)
print(element_counts)

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输出结果：

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Counter({'ab': 3, 'a': 2, 'abc': 1})

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Counter 对象 element_counts 现在包含了列表中每个元素的计数。例如，'ab' 出现了 3 次，'a' 出现了 2 次，'abc' 出现了 1 次。

按照出现次数排序

Counter 对象提供了一个 most_common() 方法，可以按照出现次数从多到少返回一个包含元素及其计数的列表。

以下是如何使用 most_common() 方法对元素计数进行排序的示例：

from collections import Counter

sample_list = ["a", "ab", "a", "abc", "ab", "ab"]
element_counts = Counter(sample_list)
sorted_counts = element_counts.most_common()

for element, count in sorted_counts:
    print(f"{element}: {count}x")

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输出结果：

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ab: 3x
a: 2x
abc: 1x

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这段代码首先使用 Counter 统计元素出现次数，然后使用 most_common() 方法获取排序后的计数列表。最后，它遍历列表并打印每个元素及其计数，格式为 "元素: 计数x"。

处理数字列表

如果你的列表包含数字，Counter 同样适用。以下是一个处理数字列表并按照出现次数排序的示例：

from collections import Counter

number_list = [1, 1, 1, 2, 2, 3]
number_counts = Counter(number_list)
sorted_counts = number_counts.most_common()

for number, count in sorted_counts:
    print(f"{number}: {count}x")

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输出结果：

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1: 3x
2: 2x
3: 1x

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完整示例

以下是一个完整的示例，演示如何从一个包含大量数字的列表中统计元素出现次数并按降序输出：

from collections import Counter

numbers = [28, 29, 31, 37, 50, 14, 28, 31, 47, 50, 9, 16, 27, 41, 45, 7, 14, 34, 41, 49, 6, 11, 16, 35, 44, 1, 12, 15, 31, 47, 9, 16, 17, 27, 31, 4, 9, 29, 34, 37, 20, 21, 30, 41, 43, 1, 7, 17, 44, 50, 10, 15, 25, 37, 46, 3, 10, 20, 36, 42, 1, 2, 6, 14, 45, 5, 12, 15, 21, 39, 13, 20, 34, 38, 43, 1, 5, 12, 18, 20, 6, 20, 27, 38, 49, 1, 18, 37, 46, 48, 4, 11, 12, 16, 42, 6, 17, 22, 39, 46, 9, 16, 32, 34, 48, 5, 18, 21, 29, 45, 8, 13, 16, 44, 47, 6, 21, 23, 26, 43, 6, 12, 36, 37, 44, 10, 11, 31, 37, 44, 1, 15, 19, 24, 33, 16, 28, 32, 36, 48, 5, 19, 33, 37, 42, 7, 11, 20, 21, 29, 16, 28, 31, 35, 42, 5, 13, 16, 41, 45, 12, 21, 24, 28, 40, 4, 8, 9, 30, 35, 11, 12, 13, 23, 26, 17, 18, 30, 33, 35, 6, 11, 29, 34, 39, 10, 27, 30, 32, 34, 28, 30, 31, 45, 46, 1, 5, 8, 20, 35, 1, 2, 11, 14, 36, 1, 3, 29, 45, 47, 2, 8, 16, 21, 39, 8, 9, 11, 13, 50, 5, 7, 21, 22, 29, 8, 13, 24, 35, 46, 11, 29, 32, 46, 47, 5, 19, 33, 36, 42, 9, 18, 30, 34, 48, 2, 3, 18, 23, 39, 7, 10, 13, 34, 47, 3, 14, 23, 41, 43, 19, 21, 23, 36, 39, 9, 18, 20, 40, 41, 11, 15, 17, 24, 46, 2, 4, 12, 31, 50, 14, 16, 24, 40, 43, 7, 16, 22, 38, 41, 3, 9, 11, 20, 39, 10, 16, 34, 36, 49, 2, 9, 38, 40, 44, 3, 17, 19, 32, 38, 6, 12, 25, 31, 37, 1, 35, 36, 38, 39, 12, 21, 23, 26, 41, 2, 16, 22, 28, 46, 8, 40, 41, 46, 47, 2, 5, 11, 27, 38, 14, 18, 20, 39, 42, 1, 13, 16, 23, 27, 9, 11, 13, 15, 25, 21, 29, 31, 46, 49, 5, 13, 43, 45, 50, 3, 8, 10, 31, 36, 8, 18, 26, 38, 39, 14, 24, 31, 44, 45, 23, 24, 38, 42, 44, 14, 24, 29, 45, 48, 13, 28, 29, 31, 47, 17, 18, 40, 43, 50, 7, 8, 12, 21, 43, 16, 23, 30, 37, 41, 6, 8, 42, 49, 50, 11, 16, 22, 34, 46, 5, 14, 35, 40, 47, 6, 15, 21, 34, 48, 6, 21, 23, 31, 39, 26, 36, 43, 47, 49, 1, 17, 22, 29, 31, 9, 30, 34, 38, 48, 4, 14, 15, 20, 28, 9, 20, 21, 22, 38]

number_counts = Counter(numbers)
sorted_counts = number_counts.most_common()

for number, count in sorted_counts:
    print(f"{number}: {count}x")

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