python中for循环如何对大于某值的数字求和_python中for循环筛选并求和大于指定值数字的方法

numbers = [10, 25, 3, 40, 12, 7, 50]
threshold = 20
total = 0
<p>for num in numbers:
if num > threshold:
total += num</p><p>print("大于", threshold, "的数之和为：", total)</p><p><span>立即学习</span>“<a href="https://pan.quark.cn/s/00968c3c2c15" style="text-decoration: underline !important; color: blue; font-weight: bolder;" rel="nofollow" target="_blank">Python免费学习笔记（深入）</a>”；</p>

大于 20 的数之和为： 115

numbers = [8, 15, 22, 33, 14, 28, 9]
threshold = float(input("请输入阈值："))
total = 0
<p>for num in numbers:
if num > threshold:
total += num</p><p>print(f"大于 {threshold} 的数字之和为：{total}")</p>
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str_numbers = ["12", "30", "5", "45", "18"]
threshold = 20
total = 0
<p>for s in str_numbers:
num = int(s)  # 转为整数
if num > threshold:
total += num</p><p>print("大于", threshold, "的数之和为：", total)</p><p><span>立即学习</span>“<a href="https://pan.quark.cn/s/00968c3c2c15" style="text-decoration: underline !important; color: blue; font-weight: bolder;" rel="nofollow" target="_blank">Python免费学习笔记（深入）</a>”；</p>

numbers = [10, 25, 3, 40, 12, 7, 50]
threshold = 20
total = sum(num for num in numbers if num > threshold)
print(total)  # 输出 115