如何利用缓存技术加速Java网站的静态资源访问？

import com.google.common.cache.Cache;
import com.google.common.cache.CacheBuilder;

public class MemoryCacheExample {
    private static Cache<String, String> cache = CacheBuilder.newBuilder()
                        .maximumSize(1000)
                        .build();
    
    public static String getResource(String key) {
        String resource = cache.getIfPresent(key);
        if (resource == null) {
            resource = // 从文件系统或者数据库中获取资源
            cache.put(key, resource);
        }
        return resource;
    }
}

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.GetMapping;
import org.springframework.web.bind.annotation.PathVariable;
import org.springframework.web.bind.annotation.ResponseBody;

import javax.servlet.http.HttpServletResponse;
import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;

@Controller
public class ResourceController {
    @GetMapping("/resource/{filename}")
    @ResponseBody
    public byte[] getResource(@PathVariable String filename, HttpServletResponse response) throws IOException {
        Path filePath = Paths.get("path/to/static/resources/", filename);
        byte[] resource = Files.readAllBytes(filePath);

        // 设置HTTP响应头，指示浏览器缓存资源
        response.setHeader("Cache-Control", "public, max-age=3600");

        return resource;
    }
}