在 Tampermonkey 中如何高效处理多个异步请求并根据条件判断控制请求的继续或终止？

function promise1() { return new Promise(resolve => setTimeout(() => resolve({data: '123'}), 2000)); }
function promise2() { return new Promise(resolve => setTimeout(() => resolve({data: '#234'}), 2000)); }
function promise3() { return new Promise(resolve => setTimeout(() => resolve({data: '1'}), 2000)); }

function mainRequest(promises) {
  return new Promise(resolve => {
    let i = 0;
    function nextRequest() {
      if (i === promises.length) { resolve('全部不符合条件'); return; }
      const request = promises[i]();
      i++;
      request.then(result => {
        if (result.data.indexOf('#') > -1) { resolve(result.data); }
        else { nextRequest(); }
      }).catch(() => nextRequest()); // 处理错误
    }
    nextRequest();
  });
}

mainRequest([promise3, promise2, promise1]).then(result => console.log('result', result));

function Promise1() { return new Promise(resolve => setTimeout(() => resolve({data: '#123'}), Math.random() * 1000)); }
function Promise2() { return new Promise(resolve => setTimeout(() => resolve({data: '#234'}), Math.random() * 1000)); }
function Promise3() { return new Promise(resolve => setTimeout(() => resolve({data: '#1'}), Math.random() * 1000)); }

function mainRequest(promises) {
  return Promise.all(promises.map(p => p())).then(results => {
    for (let i = 0; i < results.length; i++) {
      if (results[i].data.indexOf('#') > -1) { return { successIndex: i, data: results[i].data }; }
    }
    return '未找到符合条件的请求';
  });
}

mainRequest([Promise3, Promise2, Promise1]).then(result => console.log('result', result));