array binary search
Description:
Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6], 2 → 1[1,3,5,6], 7 → 4[1,3,5,6], 0 → 0
my Solution:
<span class="kw">public</span> <span class="kw">class</span> Solution { <span class="kw">public</span> <span class="dt">int</span> <span class="fu">searchInsert</span>(<span class="dt">int</span>[] nums, <span class="dt">int</span> target) { <span class="dt">int</span> i = <span class="dv">0</span>; <span class="kw">for</span>(i = <span class="dv">0</span>; i < nums.<span class="fu">length</span>; i++) { <span class="kw">if</span>(target <= nums[i]) <span class="kw">break</span>; } <span class="kw">if</span>(i < nums.<span class="fu">length</span>) <span class="kw">return</span> i; <span class="kw">else</span> <span class="kw">return</span> i++; } }
Best Solution:
<span class="kw">public</span> <span class="dt">int</span> <span class="fu">searchInsert</span>(<span class="dt">int</span>[] A, <span class="dt">int</span> target) { <span class="dt">int</span> low = <span class="dv">0</span>, high = A.<span class="fu">length</span><span class="dv">-1</span>; <span class="kw">while</span>(low<=high){ <span class="dt">int</span> mid = (low+high)/<span class="dv">2</span>; <span class="kw">if</span>(A[mid] == target) <span class="kw">return</span> mid; <span class="kw">else</span> <span class="kw">if</span>(A[mid] > target) high = mid<span class="dv">-1</span>; <span class="kw">else</span> low = mid<span class="dv">+1</span>; } <span class="kw">return</span> low; }
差别就在于,我用的是从首到尾循环,没有完全利用好已排序这个条件。最优解用的是二分法,基本是排序里的算法。
以上就是LeetCode & Q35-Search Insert Position-Easy的详细内容,更多请关注php中文网其它相关文章!
每个人都需要一台速度更快、更稳定的 PC。随着时间的推移,垃圾文件、旧注册表数据和不必要的后台进程会占用资源并降低性能。幸运的是,许多工具可以让 Windows 保持平稳运行。
Copyright 2014-2025 https://www.php.cn/ All Rights Reserved | php.cn | 湘ICP备2023035733号